WSOP 2026: Nishant Sharma Dominates Deepstack to Clinch His First Bracelet (Event #98)

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Event #98: $800 NLH Deepstack featured a total of 2,036 entries, which, even with a modest buy-in, resulted in an attractive prizepool of $1,425,200. The second day of play welcomed back 129 contenders, all vying for the six-figure winner's prize.

Much attention was on American Jason Wheeler, who had previously won this tournament in 2021. For a long time, it looked like he might repeat his success. However, Wheeler ultimately finished in third place after his hand, K d Q d, clashed with the A c A h of eventual winner Sharma.

The final showdown for the bracelet was between Nishant Sharma and Taiwanese player Chung-Tang Lin. Sharma entered the heads-up with a slight lead and quickly took control of the duel. 

In the decisive hand, Sharma put Lin all-in. After some contemplation, Chung-Tang Lin called with A h T d, while Sharma revealed K c 9 s. The flop Q c ​​​​​​​8 d ​​​​​​​9 h gave Sharma a pair, and even though the turn 7 h offered Lin hope with a straight draw, the river K d sealed Sharma's victory.

Final Table Results of Event #98: $800 Deepstack No-Limit Hold’em

Position

Player

Country

Prize

1.

Nishant Sharma

India

$196,659

2.

Chung-Tang Lin

Taiwan

$131,002

3.

Jason Wheeler

USA

$95,018

4.

Ian Schechter

USA

$69,677

5.

Steven Daly

USA

$51,663

6.

Atanas Pavlov

Bulgaria

$38,737

7.

Javier Fernandez

Spain

$29,376

8.

Alexandru Vasilescu

USA

$22,534

9.

Alexander Voros

Sweden

$17,487

10.

Nadav Avrahami

Israel

$13,730



Source: WSOP, WSOP Live

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